0=21z^2-6z+1

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Solution for 0=21z^2-6z+1 equation: 



0=21z^2-6z+1

We move all terms to the left:

0-(21z^2-6z+1)=0

We add all the numbers together, and all the variables

-(21z^2-6z+1)=0

We get rid of parentheses

-21z^2+6z-1=0

a = -21; b = 6; c = -1;
Δ = b2-4ac
Δ = 62-4·(-21)·(-1)
Δ = -48
Delta is less than zero, so there is no solution for the equation

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